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w^2-8w-345=0
a = 1; b = -8; c = -345;
Δ = b2-4ac
Δ = -82-4·1·(-345)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-38}{2*1}=\frac{-30}{2} =-15 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+38}{2*1}=\frac{46}{2} =23 $
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